y^2-y-6/3y^3-5y^2=0

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Solution for y^2-y-6/3y^3-5y^2=0 equation: 


y in (-oo:+oo)

y^2-((6/3)*y^3)-(5*y^2)-y = 0

y^2-2*y^3-5*y^2-y = 0

-2*y^3-4*y^2-y = 0

-y*(2*y^2+4*y+1) = 0

2*y^2+4*y+1 = 0

DELTA = 4^2-(1*2*4)

DELTA = 8

DELTA > 0

y = (8^(1/2)-4)/(2*2) or y = (-8^(1/2)-4)/(2*2)

y = (2*2^(1/2)-4)/4 or y = (-2*2^(1/2)-4)/4

-y = 0

-1*y = 0 // : -1

y = 0

y in { (-2*2^(1/2)-4)/4, (2*2^(1/2)-4)/4, 0 }

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